2x^2+953x+14472=33276

Solution for 2x^2+953x+14472=33276 equation:

2x^2+953x+14472=33276

We move all terms to the left:

2x^2+953x+14472-(33276)=0

We add all the numbers together, and all the variables

2x^2+953x-18804=0

a = 2; b = 953; c = -18804;
Δ = b2-4ac
Δ = 9532-4·2·(-18804)
Δ = 1058641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(953)-\sqrt{1058641}}{2*2}=\frac{-953-\sqrt{1058641}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(953)+\sqrt{1058641}}{2*2}=\frac{-953+\sqrt{1058641}}{4}
$